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OpenStudy (kira_yamato):
3π
Parth (parthkohli):
we're inversing the value of \(\sin(3\pi)\), which brings the \(3\pi\) back to us :)
Parth (parthkohli):
arcsin(sin(3pi)) means what is the angle which gets the value of sin(3pi)? Of course it is 3pi haha
Parth (parthkohli):
Arcsin(sin(x)) = x
Parth (parthkohli):
Arctan(tan(x)) = x
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Parth (parthkohli):
etcetc :)
OpenStudy (unklerhaukus):
is the domain the same?
OpenStudy (unklerhaukus):
or the range?
OpenStudy (anonymous):
i dont understand how acrsin(sin(3pi))=3pi=0 . its said that the range of acrsin is -pi/2<y<pi/2 which lies between quadrants 1 and 4. if 3pi lies in the x-axis between quadrants 2 and 3, then how is 3pi in the range of arcsin? thus how is the answer 0 ? please help
OpenStudy (unklerhaukus):
\[ y=\sin(x)\]dw:1339678093202:dw|
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OpenStudy (unklerhaukus):
at the point \(x=3\pi\)
\[\sin(x)=0\]
ie \(\sin(3\pi)=0\)
OpenStudy (unklerhaukus):
\[\arcsin(\sin(3pi))=\arcsin(0)\]
OpenStudy (anonymous):
i get that but sin(3pi) is not in the range of arcsin