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Mathematics 22 Online
OpenStudy (anonymous):

Arcsin(sin(3pi))

OpenStudy (kira_yamato):

Parth (parthkohli):

we're inversing the value of \(\sin(3\pi)\), which brings the \(3\pi\) back to us :)

Parth (parthkohli):

arcsin(sin(3pi)) means what is the angle which gets the value of sin(3pi)? Of course it is 3pi haha

Parth (parthkohli):

Arcsin(sin(x)) = x

Parth (parthkohli):

Arctan(tan(x)) = x

Parth (parthkohli):

etcetc :)

OpenStudy (unklerhaukus):

is the domain the same?

OpenStudy (unklerhaukus):

or the range?

OpenStudy (anonymous):

i dont understand how acrsin(sin(3pi))=3pi=0 . its said that the range of acrsin is -pi/2<y<pi/2 which lies between quadrants 1 and 4. if 3pi lies in the x-axis between quadrants 2 and 3, then how is 3pi in the range of arcsin? thus how is the answer 0 ? please help

OpenStudy (unklerhaukus):

\[ y=\sin(x)\]dw:1339678093202:dw|

OpenStudy (unklerhaukus):

at the point \(x=3\pi\) \[\sin(x)=0\] ie \(\sin(3\pi)=0\)

OpenStudy (unklerhaukus):

\[\arcsin(\sin(3pi))=\arcsin(0)\]

OpenStudy (anonymous):

i get that but sin(3pi) is not in the range of arcsin

OpenStudy (unklerhaukus):

\[y=\arcsin(x)\]|dw:1339678302792:dw| hence \[\arcsin(0)=0\]

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