An equilateral triangle with side of (2 times square root 3)is inscribed in a circle. What is the area of one of the sectors formed by the radii to the vertices of the triangle?

Question

An equilateral triangle with side of  (2 times square root 3)is inscribed in a circle. What is the area of one of the sectors formed by the radii to the vertices of the triangle?

anonymous · Answer

$$120/360(\pi)(2\sqrt{3})^{2}$$

anonymous · Answer

is what I did, but I'm told my answer is incorrect.

anonymous · Answer

3|dw:1339700999729:dw| this is basically what we need to find, now, you have problem with the formula?

anonymous · Answer

ok.

anonymous · Answer

you mistake? in 120/360, do you not mean 180/360?

anonymous · Answer

I thought we needed to find the length of the arc from one point of the triangle to the other point of the triangle...

anonymous · Answer

So that would mean that it would be 360/120 cause 3/120=360 and there are three sides to the triangle...

anonymous · Answer

well, im kinda confused to (probably in the same grade) its kinda,.. not my field, any how. here, is the question asking  what is the area of one of thesides in the outskirts of the triangle?|dw:1339701356675:dw|

anonymous · Answer

Yeah it's asking the length of the arc (piece of the circle) that is created by two sides of the triangle. soooo....|dw:1339701429607:dw|