An equestrian club has fourteen members. If the club wants to select a president, vice president, and treasurer (all of whom must be different), in how many ways can this be done?

Question

anonymous · Answer

14C3? or 14P3?

anonymous · Answer

@saifoo.khan  can you help please? :)

kropot72 · Answer

It must be permutations, the reason being that in each selection of 3 members the order is important because of the allocation of the office each will hold.

anonymous · Answer

2184? does that make sense

anonymous · Answer

or by bad 364

kropot72 · Answer

Good work! The correct answer is 2184 ways of selecting the 3 members.