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Mathematics 22 Online
OpenStudy (anonymous):

An equestrian club has fourteen members. If the club wants to select a president, vice president, and treasurer (all of whom must be different), in how many ways can this be done?

OpenStudy (anonymous):

14C3? or 14P3?

OpenStudy (anonymous):

@saifoo.khan can you help please? :)

OpenStudy (kropot72):

It must be permutations, the reason being that in each selection of 3 members the order is important because of the allocation of the office each will hold.

OpenStudy (anonymous):

2184? does that make sense

OpenStudy (anonymous):

or by bad 364

OpenStudy (kropot72):

Good work! The correct answer is 2184 ways of selecting the 3 members.

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