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An equestrian club has fourteen members. If the club wants to select a president, vice president, and treasurer (all of whom must be different), in how many ways can this be done?
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14C3? or 14P3?
@saifoo.khan can you help please? :)
It must be permutations, the reason being that in each selection of 3 members the order is important because of the allocation of the office each will hold.
2184? does that make sense
or by bad 364
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Good work! The correct answer is 2184 ways of selecting the 3 members.
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