Question

Simplify ? http://roads.advancedacademics.com/contentserver/content/roadssection/277575/questions/9hw3/9hw3_q2.gif

Answer 1

Hint:\[\frac{\color{red} a}{\color{blue} b} \div \frac{\color{red}c}{\color{blue}d} = \frac{\color{red}a\color{blue}d}{\color{blue}b\color{red}c}\]

Answer 2

i still dont get it, thanks though

Answer 3

Go exactly by analogy:\[\frac{\color{red}{10a^2}}{\color{blue}{7b^2}} \div \frac{\color{red}{25a^3}}{\color{blue}{14b^3}}= \frac{\color{red}{10a^2} \cdot \color{blue}{14b^3}}{\color{blue}{7b^2} \cdot \color{red}{25a^3}}\]

Answer 4

i dont know how to solve that:/

Answer 5

I'm pretty sure you do. Cancel out common factors from the numerator and the denominator.\[\frac{10 a^2 \cdot 14 b^3}{7 b^2 \cdot 25 a^3}=\frac{2 \cdot 5 \cdot a \cdot a \cdot 2 \cdot 7 \cdot b \cdot b \cdot b}{7 \cdot b \cdot b \cdot 5 \cdot 5 \cdot a \cdot a \cdot a}\]

Answer 6

4b/5a ?

Answer 7

Good job! That is correct. Does the process make sense?

Answer 8

yes it does, thank you!!

Answer 9

Cool. No problem!

Answer 10

Please give my response a medal if you thought it was helpful! :)