Question

h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.
a) 7.6 feet
b) 12.2 feet
c) 13.9 feet
d) 8.3 feet

Answer 1

r u k with differentiation?

Answer 2

To find the maximum height differentiate it first:
\(h'(t) = -16^2+32t\)
Then solve for \(t\) which is the time; then sub the \(t\) back into the height for the maximum height of the ball.

Answer 3

wait..a typo \(h'(t)=-16t+32\)

Answer 4

h'(t)=-32t+32

Answer 5

woops; sorry, \(h'(t) = -2*16t+32\) => \(h'(t)=-32t+32\) then set it to \(0\) and solve for \(t\)