Question

Plz help:-)

Answer 1

If \[\text{x+y=3 & xy=2}\] then the value of \[x^3-y^3=?\]

Answer 2

x^3 - y^3 identity kya hoti hai>?

Answer 3

\[x^3-y^3=(x-y)(x^2+xy+y^2)\]

Answer 4

(x+y)^2 = x^2 + y^2 +2xy
x^2 + y^2 = 3^2 - 2x2 = 5

Answer 5

now compute x-y

Answer 6

k! sir:)
\[\Huge{\color{gold}{\star \star}{Thanx}}\]

Answer 7

wht class?

Answer 8

viii

Answer 9

@jiteshmeghwal9 me in IX :)

Answer 10

hope that @him1618 is in 12th ?

Answer 11

2nd year

Answer 12

baat ek hi hai bhaiya ji ..... 10+2 aur 12+2 ... :)

Answer 13

@mathslover x-y ki value?

Answer 14

?????

Answer 15

abe (x-y) ko squar kar

Answer 16

= x^2 + y^2 -2xy
phir root nikal

Answer 17

samjha?

Answer 18

given
x+y=3 & xy=2

(x+y)^2 =x^2+y^2+2xy
9=x^2+y^2+4
5=x^2+y^2

(x-y)^2=x^2+y^2-2xy
(x-y)^2=5-4
(x-y)^2=1
(x-y)=1

Answer 19

at the end I get 7 but answer is 6

Answer 20

samjha bhai(munna bhai)
but answer is not correct which i m getting:/

Answer 21

@him1618 Plz

Answer 22

(x-y)^3 karke dekh

Answer 23

Itna sannata kuon hai bhai?
Is the answer wrong?

Answer 24

x^3 - y^3 -3x^2y + 3xy^2
x^3 - y^3 -3xy(x-y) = 1
Ans = 1+ 3xy(x-y)

Answer 25

aise bhi 7

Answer 26

maybe the ans is wrng

Answer 27

k! dhanyabad