Question

some body help me plzzz

Answer 1

post the question, will try

Answer 2

aww thank u

Answer 3

k here is the question

Answer 4

A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.
a) 7.6 feet
b) 12.2 feet
c) 13.9 feet
d) 8.3 feet

Answer 5

are you allowed to differentiate?

Answer 6

yes

Answer 7

i dont seem to get any of the above answers, i think it might be a tricky question...

Answer 8

yh it is any ways thank u for trying

Answer 9

the answer is 21 feet
See http://www.wolframalpha.com/input/?i=h%28t%29+%3D+-16t2+%2B+32t+%2B+5

Are you sure you don't have a typo?

Answer 10

options dont match,,ans that comes out is max height is 21 at t=1

Answer 11

there fore wt u guys think the answer gone be?? :)

Answer 12

21

Answer 13

hw ? on the choose there is no 21

Answer 14

Unless you made a mistake in the question, it is a "bogus question".

Answer 15

Okay what do you get when you take the derivative of -16x^2 + 32t + 5 ?

Answer 16

-32t + 32 so the zero is at t=1 if we put this back into the original equation we get 21 like everyone said so yeah the answers are all incorrect.

Answer 17

smthinga off..........time taken to reach max height = time to fall :P
so if t=1 is time taken..........2 shud be a root?

Answer 18

The only alternative answers I can think of are:

1. When t=0, h=5, so maybe the question is asking for the height of the ball above the starting height, in which case it would be 21-5=16 --> still no matches

2. Maybe you were also given the height of the person throwing the ball and asked to find the max height the ball reaches above this persons head?

Answer 19

@A.Avinash_Goutham your statement is only true for symmetric paths. here the starting height is 5.

Answer 20

yeah i was about to post that :P

Answer 21

@A.Avinash_Goutham If you find the roots of the original function add them together and divide by 2 you still get t=1 as a max because the roots add up to 2

Answer 22

yeah i checked that

Answer 23

i think i am late for this

Answer 24

@this u sure that qn is right?

Answer 25

yes :)

Answer 26

Graph the equation and use the MAXIMUM value on your graphing utility to find the greatest y-value.
Graph the equation and use the MAXIMUM value on your graphing utility to find the greatest y-value.

Answer 27

\[h(t) = -16t^2 + 32t + 5\]

max is at vertex, where \(t=-\frac{b}{2a}=-\frac{32}{2\times (-16)}=1\)
\[h(1)=-16+32+5=16+5=21\]

Answer 28

if you want to show off and use calculus, you can say
\[h(t)=-16t^2+32t+5\]
\[h'(t)=-32t+32\] set equal zero get critical point \[-32t+32t0\]
\[-32t=-32\]
\[t=1\]
\[h(1)=21\] no difference

Answer 29

thanks ya'all r the best :)