Mathematics
22 Online
OpenStudy (anonymous):
x = y2 - 1
2x - y = 4
(3, ) and (, )
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OpenStudy (anonymous):
quadratic system of equations
mathslover (mathslover):
i didn't understand the question completely wait
OpenStudy (anonymous):
i can post the attachment
mathslover (mathslover):
please
OpenStudy (anonymous):
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OpenStudy (anonymous):
^^
mathslover (mathslover):
So you are giving test right ?
OpenStudy (anonymous):
no this is an assignment
mathslover (mathslover):
hmn what you tried ?
OpenStudy (anonymous):
well I tried substitution, eliminations,quadratic formula, foiling...anything else and I would lose my mind
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OpenStudy (anonymous):
foiling sounds like fun...
OpenStudy (anonymous):
lol yea FUN!!
OpenStudy (anonymous):
xD
mathslover (mathslover):
ok so u r having problem in steps ...
let me give u 1st stem .. :
\(\huge{x=y^2-1}\) let this equation be 1st ..
and similarly 2x-y be the 2nd
mathslover (mathslover):
put the value of x in 2nd one..
what u get ?
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OpenStudy (anonymous):
2(y^2-1)-y=4
mathslover (mathslover):
Gr8 now simplify it by opening brackets
OpenStudy (anonymous):
2y^2-1-y=4
mathslover (mathslover):
right can u write it as \(2y^2-y-1=4\) ?
OpenStudy (anonymous):
ok \[2y^2-y-1=4\]
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mathslover (mathslover):
right transpose -1 to Right Hand Side ( RHS )
OpenStudy (anonymous):
\[2y^2-y=5\]
mathslover (mathslover):
right :
now transpose 5 to Left Hand Side again :
OpenStudy (anonymous):
\[2y^2-y-5\]
mathslover (mathslover):
= ?
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OpenStudy (anonymous):
\[2y^2-y-5=0\]
mathslover (mathslover):
right. .. what type of equation is this ?
OpenStudy (anonymous):
quadratic
mathslover (mathslover):
solve this by the following formula :
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
mathslover (mathslover):
a = 2 , b= -1 , c=-5
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OpenStudy (anonymous):
i know im working it out srry if im taking to long
mathslover (mathslover):
no problem @aussy123 u can take ur time as much u want
OpenStudy (anonymous):
\[-1\pm\frac{\sqrt{-41}}{4}\\]
OpenStudy (anonymous):
\[-1\pm\frac{\sqrt{-41}}{4}\\] \]
mathslover (mathslover):
that's right
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mathslover (mathslover):
wait but what does (3, ) mena
OpenStudy (anonymous):
thats the coordinates they are looking for
mathslover (mathslover):
wait i am calling some body good at this... or i am trying...
OpenStudy (anonymous):
okay
mathslover (mathslover):
@dpaInc
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mathslover (mathslover):
(3,2) and (5/4 , -3/2) is what i got
OpenStudy (anonymous):
how
mathslover (mathslover):
wait
mathslover (mathslover):
u did wrong in some steps ...
\[2(y^2-1)-y=4\]
\[2y^2-2-y=4\]
\[2y^2-y=6\]
\[2y^2-y-6=0\]
\[\textbf{a=2 , b = -1 , c= -6}\]
OpenStudy (anonymous):
oh ok I see lol
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mathslover (mathslover):
so shall i think that u have got the answer ?
OpenStudy (anonymous):
yea