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OpenStudy (anonymous):
Solve:
2x\equiv 3(mod 5)
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jimthompson5910 (jim_thompson5910):
Can you solve 2x = 1 (mod 5) ?
OpenStudy (anonymous):
nooo lol
jimthompson5910 (jim_thompson5910):
does 2*1 = 1 (mod 5)?
OpenStudy (anonymous):
no
jimthompson5910 (jim_thompson5910):
what about 2*2 = 1 (mod 5)?
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OpenStudy (anonymous):
no
jimthompson5910 (jim_thompson5910):
and what about 2*3 = 1 (mod 5)?
OpenStudy (anonymous):
ok x=3
jimthompson5910 (jim_thompson5910):
you got it
jimthompson5910 (jim_thompson5910):
So 2*3 = 1 (mod 5)
We want that right side to be a 3 instead of a 1, so multiply both sides by 3
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OpenStudy (anonymous):
y?
jimthompson5910 (jim_thompson5910):
2*3 = 1 (mod 5)
3*2*3 = 3*1 (mod 5)
2*(3*3) = 3 (mod 5)
2*9 = 3 (mod 5)
2*4 = 3 (mod 5)
jimthompson5910 (jim_thompson5910):
because at the top you wanted to solve 2x = 3 (mod 5)
OpenStudy (anonymous):
ohhh i get it
jimthompson5910 (jim_thompson5910):
yes, you start with 2x = 1 (mod 5), then you scale appropriately
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OpenStudy (anonymous):
2*9 = 3 (mod 5)
2*4 = 3 (mod 5)
how did u do this?
jimthompson5910 (jim_thompson5910):
9 = 4 (mod 5)
jimthompson5910 (jim_thompson5910):
since they both have the same remainder after dividing by 5
jimthompson5910 (jim_thompson5910):
9/5 = 1 remainder 4
4/5 = 0 remainder 4
OpenStudy (anonymous):
okkkk gotcha
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jimthompson5910 (jim_thompson5910):
that's great
OpenStudy (anonymous):
so x=4 not 3
jimthompson5910 (jim_thompson5910):
yes because 2*4 = 8 = 3 (mod 5)
OpenStudy (anonymous):
okkkkkk thank youuuuuuuu
jimthompson5910 (jim_thompson5910):
you're welcome
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