I have a simple question: is H = -[ 1 ]d^3 + [ 3 ]d^2
[80] [ 8 ]
always the rule used in finding the instantaneous rate of change or is it just a coincidence on my workpaper?

Question

I have a simple question: is H = -[ 1 ]d^3 + [ 3 ]d^2
                                                       [80]           [ 8 ]
always the rule used in finding the instantaneous rate of change or is it just a coincidence on my workpaper?

anonymous · Answer

Ugh, the typing came out wrong. H = -(1/80) d^3 + (3/8)d^2

anonymous · Answer

this is just a function from you previous question that gives the height of the mountain. The instantaneus rate of change of this height is the 1º derivative of this function, which is H'(d) = -(3/80) d^2 + (3/4)d

anonymous · Answer

So, in other words you are saying that it is just a coincidence, but I have no idea what you are going on about with the deriative thing.

anonymous · Answer

instantaneous rate of change is the " derivative thing"