Prove That :
___________
Cos2A+1/Sin(2A+B)+(Sec^2+1)=Cos^2A+2SinACos2A

Question

Prove That :
___________
Cos2A+1/Sin(2A+B)+(Sec^2+1)=Cos^2A+2SinACos2A

anonymous · Answer

use the addition and subtraction theorem here and simplify it. It will be easier that way. I dont give answers :) I help you acheive the answer.

myininaya · Answer

$$\frac{\cos(2a)+1}{\sin(2a+b)}+\sec^2(a)+1=\cos^2(a)+2\sin(a)\cos(2a) ?$$

anonymous · Answer

hmmm,I tried every Law extention ,But Useless...
I dont need the answer just gimme me the Key .

anonymous · Answer

Yes @myininaya ,Ty for clearifying .

anonymous · Answer

It's important to know if myininaya is right about your question?

anonymous · Answer

No-data Shes right .

callisto · Answer

Both sides are not equal?

anonymous · Answer

@Callisto :we should prove the both of them are equal .,
I copied the equation from the Book right.

cwrw238 · Answer

cos2a+ 1  = 2cos^2 a
sin(2a + b) = sin2a cos b + cos2a sin 2b

these might help

anonymous · Answer

@cwrw238 :Acually I know all law extention ,Useless .:(

anonymous · Answer

1 can be taken as Cos0..
Does it help???

myininaya · Answer

hey so just to be clear you did mean sec^2(a)+1 right?

myininaya · Answer

for that one part right?

cwrw238 · Answer

whats strange here is the disappearance of b on RHS

anonymous · Answer

@myininaya :Yes sry i forgot the a .

anonymous · Answer

@cwrw238 : I know .
If there a B ..It would be Kind easy .

callisto · Answer

Any other conditions given in the question?

anonymous · Answer

@Callisto :hmm,Not sure ..
But idk thats gonna help or not ,but this question under the topic of Identites belong to the first quad and the sec. quad .

myininaya · Answer

I think people (including myself ) agree that this is not an identity because you do not have B anywhere on the other side of the equation.

anonymous · Answer

I'am really dont know ..
Maybe I should be sure of it again .
Ty People for your help