Question

What is a Parabola with vertex at (0, 0) and directrix at x = 5 look like written in standard form?

Answer 1

Give standard form.

Answer 2

@Itz_U_Girl

Answer 3

Standard form is
(x - h)^2 = 4p(y - k), where (h,k) is the vertex, and p is the perpendicular distance of said vertex from the directrix.
the vertex being (0,0) makes things easy, it becomes
x^2 = 4py,
The distance of the vertex (0,0) from the directrix is 5, so |p|=5, but
Since the directrix is above the vertex, that suggests the parabola is concave downward, so..
p = -5

x^2 = -20y
(not entirely sure about this, your comments/corrections are welcome)