Question

Solve. 2x2 – 12x + 20 = 0

3 ± i

3 ± 2i

1 ± 2i

2 ± 3i

Answer 1

is it the last one?

Answer 2

Use the quadratic formula.

Answer 3

use the quadratic formula....\(\huge x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \)

where a, b, c are the coefficients of \(\large ax^2+bx+c=0 \)

Answer 4

yea i know that but that little i thingy confuses me

Answer 5

first simplify by 2 to get\[
2x^2 – 12x + 20 = 0\\
2( x^2 -6 x + 10) =0\\
x^2 -6 x + 10 =0\\
\]
then apply the quadratic formula as @dpalnc suggested

Answer 6

i=sqrt(-1)

Answer 7

okay

Answer 8

a=1, b=-6, c=10\\
\[\Delta = b^2 -4 ac = 36 -40= -4 \\
\sqrt{\Delta} = \pm 2 i
\]

Answer 9

the first choice?

Answer 10

yes

Answer 11

\[
\frac {6\pm 2i}{2}=3\pm i
\]

Answer 12

yea i got that.. ty

Answer 13

yw