Question

Solve for x in the proportion

Answer 1

\[\frac {4x^{2}}{8x^{2}-8x} = \frac {2}{x}\]

Answer 2

Last question for my assignment.

Answer 3

Have you learned cross-multiplication?

If so:

(x)(4x^2) = (2)(8x^2 - 8x)

-expand
-collect like terms
-isolate for x

Does that help?

Answer 4

No.

Answer 5

x = 16 and x = −16

Answer 6

x = 2!

Answer 7

(x)(4x^2) = (2)(8x^2 - 8x)

4x^3 = 16x^2 - 16x

4x^3 - 16x^2 + 16x = 0

4x(x^2 - 4x + 4) = 0

For 4x = 0:
x = 0

For x^2 - 4x + 4 = 0:

-what multiplies to 4 and adds to -4: -2, -2

x^2 - 4x + 4 = (x - 2)^2

(x - 2)^2 = 0
x - 2 = 0
x = 2

Answer 8

Yes!

Answer 9

and x = 0!

Answer 10

:]

Answer 11

But do you understand!?!?!?!