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Chemistry 19 Online
OpenStudy (anonymous):

How would you justify the presence of 18 element in the 5th period of periodic table?

OpenStudy (anonymous):

@Kryten @mathslover @maheshmeghwal9 @A.Avinash_Goutham @UnkleRhaukus

OpenStudy (anonymous):

it can be justifyed with electron configuration and Pauli exclusion principle.

OpenStudy (anonymous):

yea simple by seeing its electron congiuration as 5period means n=5 and last configuration will be ns2np6

OpenStudy (anonymous):

did nt understand!

OpenStudy (unklerhaukus):

your question is about xenon right? \[\text{Xe}\]

OpenStudy (anonymous):

take your periodic table of elements and folow this scheme http://www.chemtutor.com/images/scheme.gif

OpenStudy (unklerhaukus):

i would agree that it can barley be thought of as a nobel gas, because the properties of the nobel gasses is that they are unreactive chemically , where as Xenon can form bonds

OpenStudy (anonymous):

@Kryten i want to knoe the total number of orbitals and maximum electron that can accomodate?

OpenStudy (anonymous):

oh my one is a trick dat simply see the elctron on the orbitals but u dont know the eltron count and orbitals den u cant use it.. sorryy

OpenStudy (anonymous):

@Kryten help plzzz

OpenStudy (anonymous):

i see shamer you got even another nick open.... :) start with that scheme i gave you and folow periodic table of elements in writing of electron configuration! ill start you of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 ...

OpenStudy (chmvijay):

what exactly u want!!!

OpenStudy (anonymous):

i want to knoe the total number of orbitals and maximum electron that can accomodate?

OpenStudy (chmvijay):

that can accommodate in what!!!

OpenStudy (anonymous):

How would you justify the presence of 18 element in the 5th period of periodic table? i want to knoe the total number of orbitals and maximum electron that can accomodate?

OpenStudy (anonymous):

ok so 1s2 - stands for firs "s" orbital and 2 stands for number of electrons in that orbital so next one is 2s2 so it is second s orbital with 2 electrons, next one is 2p6 so it is second p orbital with 6 electrons and so on

OpenStudy (chmvijay):

this graph may help you 1s -first row - two protons and electrons hence 2 elements are present 2s 2p -8 protons and electrons -8 elements 3s 3p-8 protons and electrons -8 elements 4s 3d 4p-18 protons and electrons-18 element S orbital always contains two electrons and 2 protons hence can form two differnt elelmnts hence s gives rise to 2 elements similarly ,p gives rise to 6 elements and d gives rise to 10elements

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