Question

What mass, in grams, of oxygen gas (O2) is contained in a 10.5 liter tank at 27.3 degrees Celsius and 1.83 atmospheres? Show all of the work used to solve this problem

Answer 1

\[PV=nRT\]
\[1.83(10.5)=n(.08206)(300.3)\]
n=.7797 moles Oxygen

Answer 2

\[.7797 moles O _{2}\times\frac{32 g O _{2}}{1mole O _{2}}=24.95 g O _{2}\]