Question

Given:
Square with side c.
All four interior triangles are right triangles.
All four interior triangles are congruent.
The interior quadrilateral is a square.

Prove:
a2 + b2 = c2

C:\Users\Nathan Dorton\RESPONDUS\Geometry v13\Module 10\Lesson Level Assessments\10.02\images\1002_01_01.jpg

When written in the correct order, the sentences below create a paragraph proof of the Pythagorean Theorem using the diagram.

Let a represent the height and b represent the base of each triangle.

The area of one triangle is represented by the expression One halfab.

(1) The area of the

Answer 1

(2) The length of a side of the interior square is (a – b).

(3) By distribution, the area is a2 – 2ab + b2.

(4) The area of all four triangles will be represented by 4 • One half ab or 2ab.

The area of the exterior square is found by squaring side c, which is c2, or by adding the areas of the four interior triangles and interior square, 2ab + a2 – 2ab + b2.

Therefore, c2 = 2ab + a2 – 2ab + b2.

Through addition, c2 = a2 + b2.

Which is the most logical order of statements (1), (2), (3), and (4) to complete the proof?

Answer 2

So you have options or you have to write it out??

Answer 3

Optionsss..one sec



(4), (1), (3), (2)

(4), (2), (1), (3)

(4), (2), (3), (1)

(4), (1), (2), (3)

Answer 4

Sorry!!! the rest of part 1 is

(1) The area of the interior square is (a – b)2.

Answer 5

Im going to guess here and say its the first one. But im guessing so dont be mad if im wrong sorry.