Question

int 2-> infinity (1/(x^2 +4)) dx

Answer 1

int 1-> infinity (1/(x^2 +4)) dx

Answer 2

\[\int\limits_{}1/(x^{2}+4)dx=1/2 \int\limits_{}(1/2)/((x/2)^{2}+1)dx=ArcTan(x/2)/2\]

is this what you're asking?

Answer 3

\[\int\limits_{1}^{\infty}1/(x2+4)dx \]

Answer 4

well that gives ArcTan(inf/2)/2 - ArcTan(1/2)/2=pi/4-ArcTan(1/2)

Answer 5

Since ArcTan(inf)=pi/2

Answer 6

Thanks you