Question

In partial fraction,can we factorize the numerator(2x+8/(x+5)(x+3))?

Answer 1

uhmm you can..but it wouldnt make any sense? lol

Answer 2

no,we factorize denominator alwayssssssss

Answer 3

what so you mean?
like my teacher said before we begin we need to factorise.but i don't know which one

Answer 4

*do

Answer 5

@nitz Always denominator?

Answer 6

see the resolution of f(x)/g(x) into partial fractions depends mainly upon the nature of the factors of g(x)

Answer 7

ie the denominator,,,,,

Answer 8

oh!!! ok..ok I see @nitz can you solve this for me pls.

Answer 9

ya sure

Answer 10

\[A/(X+5) + B/(X+3) = (2X+8)/(X+5)(X+3) \]

Answer 11

2x+8/(x+5)(x+3)=A/(x+5)+B/(x+3)
2x+8/(x+5)(x+3)=(A(x+3)+B(x+5))/(x+5)(x+3)

Answer 12

cancel the common factors ie (x+3)(x+5) on both sides assuming them to be non zero

Answer 13

we are left with
2x+8=A(x+3)+B(x+5)

Answer 14

put x=-3,we get
2(-3)+8=A(-3+3)+B(-3+5)
2=2B
B=1

Answer 15

SImilarly put x=-5
YOU WILL GET A =1