Question

Solve the equation on the interval 0,2pi
1-cos=1/2

Answer 1

-cosx = 1/2 -1

-cosx = -1/2

cos x = 1/2

Answer 2

Can you solve from here? @axlopez23

Answer 3

write your question again............

Answer 4

is it 1-cosx=1/2

Answer 5

?

Answer 6

yes

Answer 7

pi/3, 5pi/3?

Answer 8

cos(x)=1/2
cos(x)=cos((pi)/3)or cos(5pi/3)

Answer 9

ya your answer is right

Answer 10

ok how about sin(3x)=-1?
sin is -1 at 3pi/2

Answer 11

so x = pi/2

Answer 12

so then would I use the +pi k formula?

Answer 13

hmm..................?

Answer 14

sin(3x)=-sin(pi/2)
sin3x=sin(pi+pi/2) or sin(2pi-pi/2)
sin3x=sin(3pi/2)

Answer 15

sorry

Answer 16

so x = pi/2 @nitz ?

Answer 17

ya

Answer 18

hmm ok so I know pi/2 is where sin = -1, that would be my only solution in the interval right?

Answer 19

i meant 3pi/2. Would pi/2 be part of the solution as well?

Answer 20

no only pi/2 is ur answer becoz u had to find the value of x which is pi/2
which again will the point at which sin 3x will become -1
& the angle at which the value of above function is -1 is 3x=3pi/2.
so it is the angle nt ur answer
ur answer is x=pi/2

Answer 21

ok thanks. im stuck on this last one of this type as well, tan x/2= root3. I came up with x=1, x=-1/2.