How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas?

Unbalanced equation: C2H6 + O2 → CO2 + H2O

Question

How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas? 

Unbalanced equation: C2H6 + O2 → CO2 + H2O

matt101 · Answer

Balanced: 2C2H6 + 7O2 → 4CO2 + 6H2O

x/11.7 = 6/2
x = 35.1 moles of of water are produced

35.1 mol * 18 g/mol = 631.8 g of water are produced.

anonymous · Answer

where did you get 6/2 from?  and what is x? where'd yu get 35.1? I am confused, I'm sorry.

chmvijay · Answer

see 2 moles of ethane  gives =6 moles of water
    11.7 moles of ethane gives = X moles of water (assume) cross multiplication 
                                             =(6*11.7)/2
                                           =35.1 moles

matt101 · Answer

^

Sorry I wasn't more clear. Does that make sense now @andreadesirepen?