Determine the number of real solutions of -2x² + 5x - 3 = 0.
Answers
a.2
b.1
c.0
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myininaya (myininaya):
Fine the discriminant
\[b^2-4ac\]
If <0, then 2 imaginary
If >0, then 2 real
If =0, then 1 real
OpenStudy (anonymous):
is it A,b,or c,?
myininaya (myininaya):
Plug into the expression above
What does a=?
b=?
c=?
myininaya (myininaya):
Then evaluate the expression
OpenStudy (anonymous):
a,b,c. are the answers
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myininaya (myininaya):
I know I'm telling you how to get the answer
myininaya (myininaya):
your equation is in this form
\[ax^2+bx+c=0\]
So looking at this equation what is a,b, and c?
myininaya (myininaya):
forget about your choices now
myininaya (myininaya):
We are trying to figure out what a, b, and c are in the equation you have
OpenStudy (anonymous):
.3. ok what do i do?
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myininaya (myininaya):
Trying to get you to tell me what a, b, and c are in your equation?
Your equation is in this form:
\[ax^2+bx+c=0\]
This is your equation
\[-2x^2+5x-3=0\]
myininaya (myininaya):
What is a?
OpenStudy (anonymous):
2
myininaya (myininaya):
no
myininaya (myininaya):
try again
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OpenStudy (anonymous):
-2
myininaya (myininaya):
yes! :)
now what is b?
OpenStudy (anonymous):
b=5 c=-3
myininaya (myininaya):
Ok great now plug those into the discriminant that I mentioned
myininaya (myininaya):
\[b^2-4ac \]
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OpenStudy (anonymous):
5^2-4(-2)(-3)=1
myininaya (myininaya):
OMG great! :)
Now I'm going to copy and paste what I said about the discriminant:
If <0, then 2 imaginary
If >0, then 2 real
If =0, then 1 real
myininaya (myininaya):
Which one is it?
Is 1 <0?
Is 1>0?
Is 1=0?
OpenStudy (anonymous):
1=0?
myininaya (myininaya):
No you know 1 is bigger than 0
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myininaya (myininaya):
Which on says 1 is bigger than 0?
OpenStudy (anonymous):
oo my bad 1>0
myininaya (myininaya):
Great! :)
So The conclusion is ?
myininaya (myininaya):
If >0, then 2 real
OpenStudy (anonymous):
so that answer is A?
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myininaya (myininaya):
Yes :)
myininaya (myininaya):
Good job!
OpenStudy (anonymous):
thank you.
myininaya (myininaya):
I will give you a medal for working so hard to figure it out :)