What is the equation of the line that passes through the points (-1, 3) and (1, 11)? 4x - y = 1 4x + y = 1 x - 4y = -13 4x - y = -7
any ideas? first you need the slope
What's the formula for finding the slope?
change in \(y\) over the change in \(x\)
sometimes written \(\frac{y_2-y_1}{x_2-x_1}\)
Oh yeah. Okay give me a second to to this.
ok
I got 4.
ok good
Now what is the next step?
you have a choice you can use the point-slope formula to find the equation of the line, or since you only have 4 choices you can pick the one that has slope of 4 in fact we should probably use the first method, \[y-y_1=m(x-x_1)\]
How would I set that up?
oh in fact we have to use the first method, since there are two lines with slope 4 make the number replacements in the formula \[y-y_1=m(x-x_1)\] with \(x_1=1,y_1=11, m=4\)
you should get \[y-11=4(x-1)\]
>.< Ah, I hate this part.
yeah i know, but the steps are always the same
just like yesterday
So minus the 1 from 11?
multiply out using the distributive law to get \[y-11=4x-4\] no distribute first that is always the first step
Oh yeah. Okay so. y-11=4x-4
\[(y-11)/(x-1)=(11-3)/(1+1)\] \[(y-11)/(x-1)=4\] \[4x-y=-7\]
make sure to use the distributive law to get rid of the parentheses
then you can add 11 to both sides \[y=4x+7\]
?
we had \[y-11=4x-4\] and now we want to write it in standard form
first we can add 11 to both sides to get \[y=4x+7\] is that ok?
So then we would get 4x - y = -7?
this is the "slope intercept" form from last night
then we can put all the variables on one side, the number on the other
Oh I see. I'm very slow at learning. Takes me a million times to do something before it's pinned in my small brain for good.
subtract \(y\) from both sides and subtract 7 from both sides and get the answer you wrote
of course it takes practice. you were not born knowing this
but the steps are always the same so if you do several it will become easier
we can try another if you like
Thanks for your help (: We can practice some tomorrow. I'm doing a practice assignment that is due soon.
good luck
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