Question

16n^2-4=0

Answer 1

ok first of all welcome to open study

\[\large{(4n)^2-(2)^2=(4n+2)(4n-2)}\]

Answer 2

do you want to find the value of n or just factor this ?

Answer 3

the value of n

Answer 4

16n^2=4
n^2=1/4
n=+- 1/2

Answer 5

\[\large{(4n+2)(4n-2)=0}\]
\[\large{4n=-2 , 4n=2}\]
\[\large{n=-1/2 , 1/2}\]

Answer 6

Thank you!!!!