Question

The product of (a − b)(a − b) is a2 − b2.

Sometimes

Always

Never

Answer 1

never.

Answer 2

a^2 -2ab + b^2 so never

Answer 3

\[(a-b)(a-b) = (a-b)^2\] and\[(a-b)^2 = a^2 - 2 ab + b^2 \]

Answer 4

what if a=b=0
or a=b=1

Answer 5

to make this simpler you look at the first eq first. So a * a, then you look at the 2nd part so it's b * that same a. then you do the 2nd part. b * a and then b * b.

Answer 6

Or if just b = 0

Answer 7

if b = 0 then it would be a^2 if a was 0, then it would be b^2.

Answer 8

so as a summary ur answer is sometimes:)

Answer 9

NEVAR!

Answer 10

so i think now u gt:)
btw @UnkleRhaukus @terenzreignz gave the best answers

Answer 11

sometimes dude:)

Answer 12

@KonradZuse why do u think like that?

Answer 13

Why is it sometimes?

Answer 14

The users above said 1 and 0, I already said why 0 doesnt' work.

Answer 15

becoz u r saying never but take b=0
or a=b=1
or a=b=0

Answer 16

and if it's 1 then it would either cancel out or it would be a^2 + b^2.

Answer 17

0 * anything is 0 so that would make everythign null.

Answer 18

of course cancel out:)

Answer 19

It is a Aptitude question
so depends on real domains{inputs}.

Answer 20

a^2 - 0 + 0 = a^2
0- 0 + b^2 = b^ 2

Answer 21

so LHS=RHS
it is what question wants

Answer 22

u r being confused

Answer 23

Possibleh

Answer 24

no need to confuse: -
only see this equation is sometimes true for some particular values
but without those values
it is not possible

Answer 25

@KonradZuse
Take a = 4
b = 4
you'll see that the equation holds

Answer 26

yeah that is the good idea.