Question

a+1=√b+1 for b solve

Answer 1

\[\sqrt{b}=a+1-1\]

\[\sqrt{b}=a\]
\[b=a^{2}\]

Answer 2

a. b = a2+ 2a
b. b = a + 2a2
c. b = 2a2+ a
which one?

Answer 3

\[a+1=\sqrt{b+1}\]\[(a+1)^2=(\sqrt{b+1})^2\]\[(a+1)^2 = b+1\]\[b= (a+1)^2 -1 = ...?\]
To expand (a+1)^2, you can use the identity (a+b)^2 = a^2 + 2ab+b^2

Answer 4

ans.a a^2+2a

Answer 5

\[b=a^{2}+2a+1-1\]

\[b=a^{2}+2a\]

Answer 6

@Luis_Rivera that is sqrt{b+1}.