Question

if alpha,beta are the zeroes of the polynomial p(x)=x^2+x-6,then the value of 1/alpha^2+1/beta^2.

Answer 1

\[x^{2} + x - 6 = (x + 3)(x - 2)\]

Answer 2

cn u plzzzz solve i wanna c i didn't gt d answer

Answer 3

-3 and 2 are the zeroes

Answer 4

Equate it to 0
(x + 3)(x - 2) = 0
Then either
x = -3
or
x = 2

2 and -3 are your alpha and beta :)

Answer 5

so 1/\[\alpha^2\] +1/\[\beta^2\]=????????

Answer 6

1/9+1/4

Answer 7

gt d answer thx

Answer 8

well yes you can do it like this :
there is another method :
1/a^2 + 1/b^2 = (a^2 + b^2)/(ab)^2) = ((a+b)^2 - 2ab)/(ab)^2)
here a =alpha,,b = beta..
just use the sum of roots and product of roots value,,you should get the same ans.