The slant height of the cone itself is 4 inches, and the radius of the ice cream scoop on top is 0.5 inches. What is the approximate surface area of the entire ice cream cone with the scoop of ice cream?
So for this you need the surface area of the cone without the base and half of the surface area of the sphere (that would be the ice cream scoop)
yea im not dure how to plug the numbers in
*sure
|dw:1340464723368:dw| You will need to know h for the surface area, so: h^2=4^2-.5^2=16-.25=15.75
h=sqrt(15.75)=3.9
what do i do with that?
Wait lol you don't even need the height for the surface area apparently
simple formula would be \[\pi*r(r+l) where r is the radius of the cone and l is the slant height\]
Sa of the cone = pi*r*s=pi*(1/2)*4=2pi
@THE_PROPHET that luks like gibberish to me
THE_PROPHET, in thise case we don't need the base, so your formula doesn't apply.
*correction \[\pi*r(l + 2r)\]
The surface area of a sphere is 4pir^2, but in this case we just want half of a sphere, which would be half of that, or 2pi*r^2
im still gtting large numbers
nope surface area of the scoop is 2 * pi* r^2
So: Sa(sphere)=2*pi*(1/2)^2=2*pi*(1/4)=pi/2
|dw:1340465037758:dw|
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