Ask your own question, for FREE!
Mathematics 26 Online
OpenStudy (anonymous):

The slant height of the cone itself is 4 inches, and the radius of the ice cream scoop on top is 0.5 inches. What is the approximate surface area of the entire ice cream cone with the scoop of ice cream?

OpenStudy (anonymous):

OpenStudy (agent47):

So for this you need the surface area of the cone without the base and half of the surface area of the sphere (that would be the ice cream scoop)

OpenStudy (anonymous):

yea im not dure how to plug the numbers in

OpenStudy (anonymous):

*sure

OpenStudy (agent47):

|dw:1340464723368:dw| You will need to know h for the surface area, so: h^2=4^2-.5^2=16-.25=15.75

OpenStudy (agent47):

h=sqrt(15.75)=3.9

OpenStudy (anonymous):

what do i do with that?

OpenStudy (agent47):

Wait lol you don't even need the height for the surface area apparently

OpenStudy (anonymous):

simple formula would be \[\pi*r(r+l) where r is the radius of the cone and l is the slant height\]

OpenStudy (agent47):

Sa of the cone = pi*r*s=pi*(1/2)*4=2pi

OpenStudy (anonymous):

@THE_PROPHET that luks like gibberish to me

OpenStudy (agent47):

THE_PROPHET, in thise case we don't need the base, so your formula doesn't apply.

OpenStudy (anonymous):

*correction \[\pi*r(l + 2r)\]

OpenStudy (agent47):

The surface area of a sphere is 4pir^2, but in this case we just want half of a sphere, which would be half of that, or 2pi*r^2

OpenStudy (anonymous):

im still gtting large numbers

OpenStudy (anonymous):

nope surface area of the scoop is 2 * pi* r^2

OpenStudy (agent47):

So: Sa(sphere)=2*pi*(1/2)^2=2*pi*(1/4)=pi/2

OpenStudy (anonymous):

|dw:1340465037758:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!