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Mathematics 20 Online
OpenStudy (konradzuse):

Complete the table for the radioactive isotope. (Round your answers to two decimal places.) Isotope 226Ra Half-Life 1599 Initial 250 g Find decay after 1000 Years Amount After 2,000 Year

OpenStudy (anonymous):

cool

OpenStudy (konradzuse):

y = 250e^kt

OpenStudy (konradzuse):

y = 250e^k(1599)

OpenStudy (chaise):

125=250e^(-k*1599) Make sure your k is negative, now solve for k. Do you understand how I got y=125?

OpenStudy (konradzuse):

half of 250? Other than that idk.

OpenStudy (chaise):

Yes :) because it is the half life. The time it takes for the material to decay to half of its original value.

OpenStudy (chaise):

125=250e^(-1599k) (ln(125/250))/-1599=k Make sense?

OpenStudy (konradzuse):

okies :) yup

OpenStudy (chaise):

Too easy. You got it from here, or still need help?

OpenStudy (konradzuse):

so y = 250e^((ln(125/250))/-1599) * 1000?

OpenStudy (konradzuse):

When I type that in I get 250108.0....

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