Question

Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together.

@Zarkon

Answer 1

And @siddhantsharan

Answer 2

\[7!/2!3!\]

Answer 3

Hold on. No. 120 - 24 = 96?

Answer 4

I can't be sure of the answer. To convince me you would need to show working as well.

Answer 5

In my textbook 36 is the given answer. But I don't think it's right, now that siddhant and another guy I knew answered 96 instead.

Answer 6

no. of letters= 7
no. of s = 3
no. of c = 2
therfore no. of combination= 7!/2!3!

Answer 7

Chumku read the question again.

Answer 8

know*

Answer 9

oh i get it sorry

Answer 10

lol

:( Byron left me an complicated answer. Integral and stuff.

Answer 11

a*

Answer 12

siddhan can you post the solution as well? or, a hint.

Answer 13

siddhant*

Answer 14

Yeahhh.
Sorry.
Do you want the solution or hint?

Answer 15

Actually since you're not sure, I think I should post my solution.
I may be wrong.
So,
No. of cases with no two C's together and no two S's together =
No. of cases with no two S's together ( C's can me arranged anyhow) - No. of cases with no two S's together ( C's being together now)

Answer 16

Does that seem correct so far?
@Ishaan94

Answer 17

It does

Answer 18

Writing the letters with spaces between them.
And only putting S's in the spaces so as to ensure their seperation.
Total ways of doing this ( S's together C's anyhow) :

5C2 * 4!/2!