Question

what is the equation in point-slope form of the line passing through (3, 6) an (-2, 1)?

Answer 1

You want the equation to be written as y = mx + b, where (x,y) are the coordinates of any point on the line, m is the slope, and b is the y-intercept. You have x and y already from either point given in the question.

To find the slope, find the change in rise (y) over the change in run (x):

m = (6-1)/(3-(-2)) = 5/5 = 1

You have x, y, and m, so plug all three in to y = mx + b to find b:

6 = (1)(3) + b --> b = 3

Therefore your general equation is y = x + 3

Answer 2

Thank you:) That's what I did in the beginning but y = x + 3...isn't that slope-intercept form? For my answer in point-slope form, I got y - 6 = -1(x + 3) but I think I did something wrong. Ahhh this sucks :( lol. I appreciate you helping me! I'd give you a medal on here, but I'm new to this site and I have no idea how to do that ):

Answer 3

Sorry yes for the point-slope formula, it's the same as the formula for slope. You've just multiplied both sides by x1-x2. The general formula is as follows:

y-y1 = m(x-x1)

Plugging in the numbers from above, we get y - 6 = x - 3 for the general form of the equation. You can see that this simplifies to y = x + 3, the slope-intercept form of the equation.

As for medals, just click best answer :)

Answer 4

Oh yayy :) Thank you so much!!