Question

Simplify completely 18st^4/52s^3t (times) 16s^3/9s^2t

Answer 1

Is this your problem:
\[\frac{18st^{4}}{52s^{3}t} \times \frac{16s^{3}}{9s^{2}t}\]

Answer 2

yes

Answer 3

\[\frac{18st^{4}}{52s^{3}t} \times \frac{16s^{3}}{9s^{2}t}\]\[\frac{18st^{4}}{52s^{3}t} \times \frac{16s^{3}}{9s^{2}t} = \frac{\cancel{18}2\cancel{s}t \cancel{^{4}}^{3}}{\cancel{52}13\cancel{s^{3}}t} \times \frac{\cancel{16}4\cancel{s^{3}}}{\cancel{9}s \cancel{^{2}}\cancel{t}} = \frac{2t \cancel{^{3}}^{2}}{13\cancel{t}} \times \frac{4}{s} = \frac{8t^{2}}{13s}\]

Answer 4

thank you

Answer 5

thank you

Answer 6

thank you

Answer 7

thank you

Answer 8

No Problem :)