Question

Solve the following equation.
(x - 3) /x = (x - 3) / (x - 6)

Answer 1

Cross multiply.

Answer 2

Now divide both sides by (x - 3)

(x - 6) = x

O My God, no solution...

Answer 3

@jiteshmeghwal9 please solve it further and tell what is the answer...

Answer 4

@jiteshmeghwal9 How in the world did you get from the original equation to THAT? Looks like you multiplied the numerators to each other and the same for the denominators.

Answer 5

That's not cross multiplication though!

Answer 6

Oh! i m sorry.

Answer 7

The original equation is:
\[\frac{x-3}{x} = \frac{x-3}{x-6}\]

Answer 8

(x-3)(x-6)=(x-3)(x)
x^2-6x-3x+18=x^2-3x
x^2-9x+18=x^2-3x
x^2-x^2-9x+3x=-18
-6x=-18
x=-18/-6=3.

Answer 9

Am i correct now.

Answer 10

@Wired & @waterineyes

Answer 11

Yes and no. While it solves your equation, put X into the original equation. You're dividing into zero.

Answer 12

I m only giving the value of the ques.

Answer 13

'x' in the ques

Answer 14

In the first part of your equation you can just remove (x-3) from both sides, coming back to what was said earlier (now deleted) where 0=6.

With your equation you get (0/3)=(0/-3) aka 3=-3. Another impossibility.

Answer 15

\[\frac{x - 3}{x} =\frac{x -3 }{x - 6}\]

So you guys crossed multiplied

By the way x cannot be 0, x-6 cannot be 0 because if these are zeros then the expressions evaluated at those particular values for x then one of the sides will not exist while the other side has a value that does exist.