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a silver ball weighing 50g is removed from a furnace and dropped into a 350g of water at 0°C. if the equilibrium temperature is 10°C and the specific heat capacity of platinum is 230J〖kg〗^(-1)〖°C〗^(-1), what is the temperature of the furnace? neglect the effect of the mass of the calorimeter.
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315
can you explain? i really have no idea how to do this. :(
q=mct so,heat absorbed by water=350*1*10=3500 and this(3500) is heat released by silver ball so, 3500=0.23*50*t t=314 this t is change in temp so, temp of ball=314=10=315
oops.......t=304 so temp=304+10=314
thank you very much! :) god bless you :)
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Well, that could not be more wrong :)
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