MIT 6.002 Circuits and Electronics, Spring 2007
20 Online
OpenStudy (anonymous):
How to solve? I tried KCL with variables but the variables kept canceling out.
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OpenStudy (anonymous):
Pic:
OpenStudy (ash2326):
I'll help you, let me mark the voltages
OpenStudy (anonymous):
Thank you.
OpenStudy (ash2326):
Notice where I've taken ground, with respect to it, voltages are marked
OpenStudy (anonymous):
OK
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OpenStudy (anonymous):
okay how do u solved
OpenStudy (ash2326):
Now write node equation at node, marked with voltage V, can you write?
OpenStudy (anonymous):
-V+ ((12-V)/2) -4 = 0
OpenStudy (anonymous):
Right?
OpenStudy (ash2326):
A small error, it'd be
\[\frac{0-V}{1K}+\frac{12-V}{2K}+4 mA=0\]
\[-V+\frac{12-V}{2}+4=0\]
Now find V from this
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OpenStudy (anonymous):
r u sure ash
OpenStudy (ash2326):
yeah, summing all the incoming currents
OpenStudy (ash2326):
*outgoing
OpenStudy (ash2326):
Omg, I'm doing wrong
OpenStudy (ash2326):
Let me rewrite
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
OK
OpenStudy (ash2326):
this is correct, summing all incoming currents
\[-V+\frac{12-V}{2}+4=0\]
OpenStudy (anonymous):
Why don't you subtract 4 mA, since it is incoming.
OpenStudy (anonymous):
*?
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OpenStudy (ash2326):
I have all incoming currents
OpenStudy (anonymous):
yeah keep going
OpenStudy (anonymous):
But why is the first term -V? Shouldn't it be positive V since it is incoming?
OpenStudy (ash2326):
|dw:1340648951824:dw|
A and B are potentials