Question

derivative of 5e^(3(x^2))

Answer 1

\[5e^{{3x}^2}\]

Answer 2

so I guess to start it off we get rid of the 5 and put it to the left so we worry about only e^blah.

Answer 3

u = 3x^2 du =9x

So it's going ot be e^u = e^u * u'

Answer 4

so that should leave us with 5 * 9x * e^((3x)^2)?

Answer 5

I cant help sorry not that advanced

Answer 6

np ty

Answer 7

http://www.wolframalpha.com/input/?i=derivative+of+5e%5E%28%283x%29%5E%282%29%29

This is what wolfman is saying, but I'm not sure if I get exactly how it's happening.

Answer 8

I guess we do the (3x)^2 first to get the 9x, but I would also think the derivative of 3 would be needed?

Answer 9

\[d[5e^{3x^{2}}]/dx= 5e^{3x^{2}}*6x=30x5e^{3x^{2}}\]

Answer 10

just chain rule

Answer 11

That's what I thought so what exactly is wolfman doing?

Answer 12

idk

Answer 13

I guess I see how they are starting off.

Answer 14

5e^9x^2

Answer 15

18x * 5e^9x^2

Answer 16

okay that makes sense now...

Answer 17

ah sry (3x)^2 or 3x^2

Answer 18

?

Answer 19

(3x)^2

Answer 20

I confused myself with that too.

Answer 21

oh, then is different...

Answer 22

actually....

Answer 23

I guess it is just 3x^2

Answer 24

Im sorry I suck lol :p

Answer 25

\[d[5e ^{9x ^{2}}]/dx=90x5e ^{9x ^{2}}\]

Answer 26

sry 5 is a typo

Answer 27

90xe^9x^2