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derivative of x^6 *e^x = u'v + v'u 6x^5 * e^x + e^x * x^6.... Can I said 2e^x?
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or is it(6x^5 * e^x) + (e^x * x^6) ?
it is what you said before you simplified \[6x^5e^x+x^6e^x\] if you like you can factor out the common factor of \(x^5e^x\)
So I cannot do 2e^x?
in which case you would get \(x^5e^x(6+x)\)
no \(e^x+e^x=2e^x\) but that is not what you have here
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So it os like (6x^5 * e^x) + (e^x * x^6) they stay seperate...?
is*
yes or you can factor as i wrote above
okies ty :).
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