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OpenStudy (anonymous):
[Part 1] Show all work in dividing the fraction of 3 k squared plus k minus 2 over 4 k minus 2 divided by the fraction of k squared plus 3 k plus 2 all over 2 k squared plus 5 k minus 3.
[Part 2] Use complete sentences to explain your process.
14 years ago
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OpenStudy (anonymous):
multiply by the reciprocal just like you would do with numbers
\[\frac{3k^2+k+2}{4k^2-2}\times \frac{2k^2+5k-3}{k^2+3k+2}\]
14 years ago
OpenStudy (anonymous):
then factor and cancel like before
14 years ago
OpenStudy (anonymous):
\[\frac{3k^2+k+2}{4k-2}\times \frac{2k^2+5k-3}{k^2+3k+2}\]
14 years ago
OpenStudy (anonymous):
@satellite73 are you a teacher? student?
14 years ago
OpenStudy (anonymous):
typo in my first one
@Trexy will show you how to factor
14 years ago
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OpenStudy (anonymous):
i am a car
14 years ago
OpenStudy (anonymous):
@HayleyWhite17 you got the factoring part?
14 years ago
OpenStudy (anonymous):
No really, Im asking cuz their is a diffrent between a teacher and a student, you know what i mean..@satellite73
14 years ago
OpenStudy (anonymous):
No not quite.
14 years ago
OpenStudy (anonymous):
\(x\) should be \(k\)
14 years ago
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OpenStudy (anonymous):
dang lots of typos but you can fix it
14 years ago
OpenStudy (anonymous):
\[=\frac{(k+1)(3k-2)(k+3)(2k-1)}{2(2k-1)(k+2)(k+1)}\]
14 years ago
OpenStudy (anonymous):
No I get what it is THANKS!
14 years ago
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