Question

Indicate in standard form the equation of the line passing through the given points.

B(0, 0), C(4, -4)

Answer 1

All right, here is our graph with points B and C shown. Now, can you show me an equation for a line?

\[y=m*x + b\] is common equation for a line.

Answer 2

You can determine the slope, m. Then you can determine the y-intercept which is what b is.

Answer 3

You can compute the slope by
\[ m= \frac{y2 - y1}{x2 - x1}\]

Where you have two points: B and C
B = (0,0) = (x1, y1)
C = (4, -4) = (x2, y2)

Therefore, using these values to obtain the slope, m:

\[ m= \frac{(-4) - 0}{4 - 0}\]

Now simplify that.

Answer 4

Once you have m, plug it in the equation \[y=m*x + b\]. Then you can use one of the points to determine what b is in the equation:

Here, using point B, where B = (0,0) = (y,x)

0 = m*0 + b

Solve for b

Answer 5

That is an approach that should get you the answer: give it a try, and I can check your work for you once you have a solution ;)

Answer 6

thank you :)

Answer 7

No problem, I hope it is clear. Please ask if you have any questions or need clarification.

Answer 8

ok sounds good thanks again :)