Question

Please help!
Solve the following applied problem using a system of equations.
The sum of two numbers is 56. If the smaller number is 1/3 the larger number, what are the two numbers?
If x is the smaller number, one equation is:
a. x-y=56
b. x y=56
c. x/y=56
d. x+y=56

Answer 1

So sum of these two number in question is 56; x+y=56 this will be your first equation.

Answer 2

If the smaller number (x) is 1/3 the largest number, we have 1/3y = x

Answer 3

Oh I see. So, c.? Can you please confirm?

Answer 4

Should be D)

Answer 5

\(x+y=56 \\x=\frac{1}{3}y\)

Answer 6

Oh I get it now.

Answer 7

Thank you zepp!

Answer 8

You are welcome :)