Please help! Solve the following applied problem using a system of equations. The sum of two numbers is 56. If the smaller number is 1/3 the larger number, what are the two numbers? If x is the smaller number, one equation is: a. x-y=56 b. x y=56 c. x/y=56 d. x+y=56
So sum of these two number in question is 56; x+y=56 this will be your first equation.
If the smaller number (x) is 1/3 the largest number, we have 1/3y = x
Oh I see. So, c.? Can you please confirm?
Should be D)
Oh I get it now.
Thank you zepp!
You are welcome :)