I knew the formula but i forgot. :/
That link might help.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (maheshmeghwal9):
k.
thanx:)
OpenStudy (saifoo.khan):
Np! (:
OpenStudy (anonymous):
u can find distance by using ut+1/2at2
OpenStudy (maheshmeghwal9):
I m nt getting
Plz u find:) @Ruchi.
OpenStudy (maheshmeghwal9):
Are u getting \[S= \frac{a}{2 \alpha}?\]
then u right 100%
then plz tell me:)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (vincent-lyon.fr):
Hi Mahesh! Distance travelled is distance out + distance return.
Here, both distances are equal.
So you only need to find distance out, which is equal to displacement from starting point when velocity becomes zero.
You will find \(S= 2\Large \frac{a}{4 \alpha}=\frac{a}{2 \alpha}\)?
Is that clear?
OpenStudy (maheshmeghwal9):
k! thanx a lot sir:)
but wt did u do to find \[\frac{S}{2}=\frac{a}{4 \alpha}.\]?
OpenStudy (maheshmeghwal9):
only give me hint sir:)
OpenStudy (vincent-lyon.fr):
You get time of U-turn when you write velocity = 0
Then plug it in in s(t)
OpenStudy (maheshmeghwal9):
k.
sir thanx a lot lot:)
Still Need Help?
Join the QuestionCove community and study together with friends!