Question

Use the given zero, r=5, to find all the zeros of the function. f(x) = x^3+x^2+9x+9,

Answer 1

You'll have to factor this out;
\(\large x^3+x^2+9x+9\\x^2(x+1)+9(x+1)\\(x^2+9)(x+1)\)

Answer 2

Now, zeros are also called x-intercept, these are the values of x when y = 0.

Answer 3

If one root is 5 then it must satisfy this equation..

So, factor will be : (x - 5)

Divide the given equation by (x - 5) and then solve you will get the other roots too..

Answer 4

Set one side to 0;

\(\large (x^2+9)(x+1)=0\)

Then you'll have to solve for x
\(\large (x^2+9)=0 \\ x^2=-9 \\ \sqrt{-9}=x=3i\)

And \(x+1=0;x=-1\)