Question

Find the area of a square with side length 1 – 3x.
A. 1 + 9x2
B. 1 - 9x2
C. 1 - 6x + 9x2
D. 1 - 6x - 9x2

Answer 1

The area of a square is the side squared. So you square 1 - 3x.

\( \color{Black}{\Rightarrow (1 - 3x)^2}\)

\( \color{Black}{\Rightarrow (1 - 3x)(1 - 3x)}\)

Answer 2

\[(1-3x)^2\]

Answer 3

\( \color{Black}{\Rightarrow 1(1 - 3x) - 3x(1 - 3x) }\)

Answer 4

Area of a square=side*side

Answer 5

\( \color{Black}{\Rightarrow 1 - 3x - 3x + 9x^2}\)

Answer 6

Area of Square = \[(Side Length)^2\]

And Remember:

\[(a - b)^2 - a^2 + b^2 - 2ab\]

Here, a = 1 and b = 3x

Put and solve it...

Answer 7

=\[(1)^2+(-3x)^2-2(1)(3x)\]\[=1+9x^2-6x\]
therefore C

Answer 8

C again -.-