Question

Find the volume of the solid that is obtained when the region under the curve over the interval [5, 24] is revolved about x-axis.

Answer 1

bakaloria student?

Answer 2

please see the attached file

Answer 3

are you doing bakaloria?

Answer 4

@agrin no, I dont

Answer 5

find the integral of the function, put x= 5 and put the equation equal 5, and then youll find C

Answer 6

do you have a sketch of the graph?

Answer 7

I got this answer 696.39

is it correct answer??

Answer 8

put the eq equal to 24*

Answer 9

like "24 = integral of function (put x=5) + C"

Answer 10

you have to find C

Answer 11

I have to find the volume

Answer 12

you can do this by integration

integral of pi ((x+3)^)(2./3) between x = 5 and x = 2424

Answer 13

and I got the answer 696.39

I want to know if this answer is correct or not?

Answer 14

then B =24 , A=5 and solve the functions, find its integral

Answer 15

integral of (x+3)^2/3 = { (x + 3)^(5/3)] / 5/3

Answer 16

= 3/5 (x+3)^(5/3)

Answer 17

Here is my solution, please see if this is correct or if not then tell me how do I solve this and what formula should we apply in this situation ..

Answer 18

your integration is incorrect - its what you got * 3/5