Question

solve the following system:
x2 - y = 3

x - y = -3

Answer 1

rearrange the first eq. to get:
y=x^2-3
and the second to get:
y=x+3

then equate these two to get x (hint you'll get a quadratic)

Answer 2

Subtract equation#2 from equation#1, and you should get a quadratic in 'x'. Solve it to find out 'x', and then substitute the values to find out 'y'.

Answer 3

x-y= -3 , x = -3+y

(x)^2 - y = 3
(-3+y)^2 - y = 3
y^2 -6y + 9 - y =3
y^2 -7y+6 = 0
(y-1)(y-6) = 0
y=1, y=6

Answer 4

thanks everybody

Answer 5

Don't forget also to solve for x, by substituting y into the original equation