Question

the number of real solutions of x-1/(x^2-25) = 5 - 1/(x^2-25) is?

Answer 1

@Yahoo! did you try this?

Answer 2

i have no idea

Answer 3

i think i must cross multiply

Answer 4

Yeah, do that;D

Answer 5

naah, easier thing,

Answer 6

so it will be cubic equation!

Answer 7

\[x-1/x ^{2}-5\]

Answer 8

Yeah, it's a cubic.
Could you write what do you get?

Answer 9

how to solve cubic equation!

Answer 10

=\[x/(x ^{2}-5) -1/(x ^{2}-5)\]

Answer 11

cut -1/x^2-5 from both side

Answer 12

hey u got my question wrong @mathslover plzz lokk it once again

Answer 13

x - 1/(x^2-25)

Answer 14

so u have x/x^2-5=5
x=5x^2-25

Answer 15

@dg123 @mathslover x - 1/(x^2-25)

Answer 16

oh wait

Answer 17

ooooh

Answer 18

then there is only 1 solution tht is 5

Answer 19

the answer should be 0

Answer 20

@ash2326 plzz help confused

Answer 21

the answer is 0, yeh bcoz the solution u get is 5, but it cant be putted on the denominator or else it will make the denominator =0

Answer 22

which aint happening

Answer 23

plzz @dg123 can u show the stepssssss

Answer 24

yeh i am giving

Answer 25

x-(1/x^2-5)=5-(1/x^2-5)
add 1/x^2-5 on both sides, u get
x=5

Answer 26

so according to u it is 1 but it should be 0

Answer 27

but look at the term 1/x^2-25
if u put x=5, the denominaot turns 0

Answer 28

@Yahoo! would u write the cubic equation which u gt?

Answer 29

but dividing by zero is not possible, so there is no solution

Answer 30

i think that i did the answer @Yahoo! will that be helping u ?

Answer 31

@Yahoo! when we cancel the terms from both side, we assume that x is not 5, but on solving we get x=5
so there is no real solution for this

Answer 32

in a nutshell, ( we get one solutio which is 5 but it makes the terms undefined, so there is no solution)