Question

CAN YOU CHECK MY PROBLEM??!!

Answer 1

Hey that's the problem you posted yesterday

Answer 2

probably but this is the one with my answer...obviously the other one was incorrect

Answer 3

Replace n with 6 and 7, as I said yesterday

Answer 4

ITS of the form 1/n^3

Answer 5

@mathslover Nah it's geometric, and the formula is given

Answer 6

oh sorry u may carry on i did mistake there

Answer 7

\( \color{Black}{\Rightarrow {1 \over 6^3}}\)

\( \color{Black}{\Rightarrow {1 \over 7^3}}\)

Just find these two ^

Answer 8

6^3 = 6 * 6 * 6
7^3 = 7 * 7 * 7

Answer 9

so 6th term and seventh term would be \[1/6^{3} and 1/7^{3}\]

Answer 10

I have 1/216 and 1/343 now

Answer 11

CORRECT ^ :D

Answer 12

its simpler, as i said previously, apply those two terms.. one is getting divided by successive number raised to power of 3..

so 1/6cube and 1/7cube... i.e 1/ 216 and 1/343

Answer 13

THANKS EVERYONE!! :)