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Mathematics 21 Online
OpenStudy (anonymous):

Let S be the set of all people in the world, a and b be people in S, and R be the relation given in each item below. Is (S,R) a partially ordered set? i) a = b or a is a descendant of b ii) a and be do NOT have a common friend

OpenStudy (anonymous):

I answered Yes for i) and No for ii) by the way

hero (hero):

Did you get this question from a textbook?

OpenStudy (anonymous):

i rephrased it a little to shorten the question.. is there something wrong with the way I rephrased it?

hero (hero):

Post the question exactly as it is from the book, then post the name, author, and edition of the book.

OpenStudy (anonymous):

Um, okay, this is from Kenneth Rosen's Discrete Mathematics and Its Applications, 7th ed. Here's a screenshot from the book too: https://dl.dropbox.com/u/17638088/prob.PNG

hero (hero):

k

OpenStudy (anonymous):

I only need parts c and d from the problem in the book by the way

OpenStudy (anonymous):

Why do you need the author, title, ed, etc of the book?

hero (hero):

To see if I had the book. Hang on

OpenStudy (anonymous):

Oh okay..

hero (hero):

Which chapter are you working on?

OpenStudy (anonymous):

9.6, Partial Orderings

hero (hero):

Standby

hero (hero):

Recall the following: A relation, R, on a set A is (i) Reflexive of (a,a) ∈ R for all a ∈ A (ii) Anti-symmetric if (a,b),(b,a)∈R implies that a = b (iii) Transitive if (a,b),(b,c) ∈ R implies that (a,c)∈ R (iv) A partial ordering if it is reflexive, anti-symmetric and transitive. Suppose S is the set of all people in the world: (a) R = {(a,b) ∈ R | a is no shorter than b} is a relation on S. Then, R is not anti-symmetric because there may be two different persons with the same height. Hence, (S,R) is not a proset. (b) R = {(a,b) ∈ R | a weighs more than b} is a relation on S. Then R is not reflexive because no other person weighs more than him or herself.

hero (hero):

Hence, (b) is not a proset either

OpenStudy (anonymous):

Thank you, but I only need parts c and d, as I've said above :D

hero (hero):

You are correct then, lol

hero (hero):

But you should post a more complete answer than just yes or no

OpenStudy (anonymous):

Haha thanks, just want to make sure. My teacher said she doesn't require the actual explanation.

hero (hero):

Yes, but that is the proper way to answer the questions. Yes or No are technically not mathematical responses.

hero (hero):

If I were the teacher, I would tell you that these are not "Yes" or "No" questions.

OpenStudy (anonymous):

Haha that would be my inclination as well. I'm going to ask her again.

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