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\[\sum_{n=1}^{\infty} \frac{\sqrt(n^{2}-1)}{n^{3}+2n^{2}+5}\] limit comparison test \[\frac{\sqrt(n^{2})}{n^{3}}\] \[\lim_{n \rightarrow\infty} \frac{1}{n} =0 \] convergent correct?
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\[ \sum_{n=1}^{\infty} \frac{\sqrt(n^{2}-1)}{n^{3}+2n^{2}+5} \leq \sum_{n=1}^{\infty} \frac{\sqrt{n^{2}}}{n^{3}} = \sum_{n=1}^{\infty} \dfrac{1}{n^2}\] 1/n^2 converges ... don't compare it with 1/n ... 1/n diverges.
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