Prove that A∩(AUB)=A
Wow, this thing is bugged. Anyway. A intercept ( A U B ) = A intercept A + A intercept B Now realise this: If a does intercept B, then the interception is already in A! So you get A intercept (A U B) = A intercept A + A Intercept B = A + something already within A = A
And oh, if A does NOT intercept B then A intercept B is just zero anyway, and you get the same result.
Sorry but I find your post really confusing.
The equation thing isnt working. You know that A intercept ( A U B ) = (A intercept A) U (A intercept B), correct?
no I did not know that
Well, thats a given rule. But in simpler terms you can think of it this way: first do the union, you get A U B, which is the space of A plus the space of B. Then do the intercept with A. That yields the space that is equal to A. Well, if you began with A+B then you end up with just A again.
ok yeah its makes sense using venn diagrams.
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